It looks like you're new here. If you want to get involved, click one of these buttons!

- 14.8K All Categories
- 7.7K General
- 22 Announcements
- 6.1K Off Topic
- 1.3K Playground
- 356 Suggestions & Bug Reports
- 2K General Discussion
- 782 Help
- 932 Bug Reports
- 1.9K Suggestions
- 130 Legacy
- 18 General Discussion
- 30 Help
- 45 Bug Reports
- 37 Suggestions
- 1.1K Idle Game Maker
- 428 Developer's Lounge
- 79 Games
- 45 Suggestions & Bug Reports
- 363 Games - Old
- 355 RandomGen
- 355 General Discussion
- 41 Nested
- 41 General Discussion

Please read the forum rules before posting.

Check if you are posting in the correct category.

The Off Topic section is not meant for discussing Cookie Clicker.

Check if you are posting in the correct category.

The Off Topic section is not meant for discussing Cookie Clicker.

bob_32_116
Member Posts: **770** ✭✭✭

These are based on the standard formula from elementary maths for the sum of terms in a geometric progression, where

a = first term

n = number of terms

r = ratio between successive terms

The sum is a(r^n -1)/(r-1)

(1) Cost of acquiring n of a building

C = cost of next building

r = 1.15

cost of n buildings is C*(1.15^n - 1)/0.15

(2) Cost of replacing n buildings (eg. after sacrificing 100 to unlock an aura)

Here we are going down the sequence instead of up. Each building is cheaper than the one before. Here r = 1/1.15

cost = C/1.15 * (1/1.15^n - 1)/(1/1.15 - 1)

= C * (1 - 1/1,15^n)/0.15

n is normally 50, 100, or 200, making the term 1/1.15^n so tiny that the cost is effectively just C/0.15.

(3) Cookies released by selling n of a building

Just multiply the formula in (2) by the resale factor f:

Cookies released = f * C * (1 - 1/1,15^n)/0.15

f = 0.5 (or 0.85 if Earth Shatterer is active).

Cookies obtained from selling ALL buildings, if you have more than a couple of dozen of them, is very close to f * C/0.15.

a = first term

n = number of terms

r = ratio between successive terms

The sum is a(r^n -1)/(r-1)

(1) Cost of acquiring n of a building

C = cost of next building

r = 1.15

cost of n buildings is C*(1.15^n - 1)/0.15

(2) Cost of replacing n buildings (eg. after sacrificing 100 to unlock an aura)

Here we are going down the sequence instead of up. Each building is cheaper than the one before. Here r = 1/1.15

cost = C/1.15 * (1/1.15^n - 1)/(1/1.15 - 1)

= C * (1 - 1/1,15^n)/0.15

n is normally 50, 100, or 200, making the term 1/1.15^n so tiny that the cost is effectively just C/0.15.

(3) Cookies released by selling n of a building

Just multiply the formula in (2) by the resale factor f:

Cookies released = f * C * (1 - 1/1,15^n)/0.15

f = 0.5 (or 0.85 if Earth Shatterer is active).

Cookies obtained from selling ALL buildings, if you have more than a couple of dozen of them, is very close to f * C/0.15.

Post edited by bob_32_116 on

0